O.K. I'll take another shot at this Lets say that when the reluctor is lined up with the pick up, a spark shoots out of the coil.(it may happen on the rising edge or falling edge, but lets make this easy)
When the distributor is at rest, and the pick up and reluctor are lined up with each other, the rotor is aimed dead center at the cap terminal. I have the distributor here and I see this as true. YES
Now lets add 10 (distributor)degrees of mechanical advance.
This seems to be where everyone starts to disagree.
The way I see it: The coil will only fire when the reluctor and pick up are aligned. CORRECT
The way some see it: The rotor is 10 degrees ahead of a cap terminal when the spark occurs. IT WONT BE,IT'LL STILL BE DEAD EVEN
Since a spark only occurs when the reluctor and pick up align, how can this be? SEE ABOVE
How is the spark triggered if the reluctor is not in line with the pick up?
SPARK IS TRIGGERED WHEN RELUCTOR IS IN LINE WITH PICKUP. Trendz would you take 3 minutes & do the dist test in your hand. You will see the "magic", how the last three statements will take place even tho it makes no sense. Just now I went into the kitchen & tried it again (just to keep my sanity!). EDIT Keep in mind, you are checking rotor position at idle/no advance with tooth lined up then you are moving the tooth a bit CCW then twisting the reluctor CW so it will fire earlier (the mech adv) which is what would happen when running & mech adv is advancing it and at that point when it fires (earlier) the tooth is lined up with the magnet and the rotor is back to its original position
Trend is agreeing with you, he doesn't need to see the magic.
Boy, no wonder this is so confusing for Everybody.
