If it were the same system if you up the voltage you up the current.
math says so.

I=V/R

how can current go down by doubling voltage without changing resistance?

1 = 1/1

2= 2/1

where do you get half the amps?

The only way to get half the amps is if resistance changed.
motors wired for 24 volts are not the same as 12 volts.

I am open to being wrong, but your math doesn't make sense.

I cannot take a 24 volt motor and plug it into 12 volts and have it work. it won't run.

yes I can have a 12 volt motor run on 24 volts, but it will burn out eventually because it wasn't set up to handle that voltage.


I guess I will ask, how do you make the math work then?
what did I miss.
If I change voltage from 12 volts to 24 volts I use less amps to drive the same amount of work.
but how do you get the I=V/R equation to work? If R is constant then when V goes up so must I.
but you are telling me it goes down?