I have installed a Strange Dana 60 in my Hemi Challenger and I am trying to get the right length driveshaft. I bought a slip yoke from Strange (1350 u joints). Their website says to bottom out the slip yoke in the trans take the measurement and then subtract 1".

This leaves me with a 45.62 long driveshaft. The charts say my driveshaft should be 44.60 long. Did Ma Mopar allow 2" from bottomed out in the trans?

The car had an 8 3/4 in it and the driveshaft was 45.25 long. The charts say it should have had a 45.60 long driveshaft. I asked Strange and they informed me their stuff is the same dimensionally as the originals.

Any help will be appreciated.
Thanks

Anyone?

I just talked to a different guy at Strange and he told me their slip yoke is 1" shorter than stock and that is where the difference is.

Original 7290 slip joint.
8 5/16" OAL
7 9/16" Center of u-joint to end of shaft.

Looks like the Strange slip-joint is an 1 1/2" shorter. I wonder how much it sticks out the end of the transmission when it is bottomed out?

U1666 Mopar, Doug Nash, & Liberty / 30-spline / 1350
series (Strange Stainless Steel) (G= 6.062 H= 1.680)... $179.00

Maybe I'm missing something but the length of the part that slides into the tranny won't affect the DS length.

44.6 should be the correct number.

Here is a picture of the slip-joint I posted, bottomed out in a 70 E-Body A833 transmission. It sticks out about 2 1/4" from the end of the housing to the center of the u-joint (7290).

It appears that the only thing you get with a shorter u-joint is a shorter stroke and premature dropout.

That's the measurement you need.

What's the measurement between the U-joint centerline to the base (not including the barrel part that slides in the tranny).

If the 1350 is 1" shorter than the 7290, then you need a 1" longer DS.