Originally Posted by 6PakBee
I'm sorry, I just don't buy the approach of using the force of only one side of a multi piston fixed caliper to calculate force. Let's say you had two porta-power rams between two fixed supports with the pistons opposing each other with a block between them. If you pump one porta-power to a given ram pressure and then pump the other porta-power to the same ram pressure, you guys are saying the second one didn't contribute any additional force? shruggy

Brain fart. I get it. In my example, the second ram is mechanically opposing the force of the first ram. If you pressurize the second ram to the same pressure as the first, you are simply substituting the mechanical opposition with hydraulic opposition, there is no additional force supplied. Got it.


Here’s a brake calculator and shows you have to calculate forces

https://brakepower.com/help_abc_27_PAC_t.htm